Published by:
CGP EDU Academic Team
Published on: August 14, 2026
A 100 ml solution of 0.1 n HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30 ml of NaOH solution. The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is
Text Solution
Verified by ExpertsThe correct answer is:
D
Volume m of HCl neutralised by NaOH = (Caustic soda) = 
; 
; 
V total ( HCl ) = 100 ml
40 ml 0.1 N HCl is now neutralised by KOH (0.25 N ) 
( HCl ) 
( KOH )
; 
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Mixture of sand and sulphur may best be separated by
Irrespective of the source, pure sample of water always yields 88.89% mass of oxygen and 11.11% mas…
Zinc sulphate contains 22.65% of zinc and 43.9% of water of crystallization. If the law of constant…
10 of gas and 10 of gas X at the same temperature contain the same number of molecules. The gas …
The molar heat capacity of water at constant pressure is 75 . When 1.0 kJ of heat is supplied to 1…
A compound possesses 8% sulphur by mass. The least molecular mass is